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JEE Advance 2025 Paper 1

JEE Advance · 2025

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SHORT ANSWER4 marks

Elevator height y=8[1+sin(2πt/T)]y = 8[1 + \sin(2\pi t/T)]  , T=40πT = 40\pi   s. Object mass 50 kg. Max variation of weight (in N) is?

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