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JEE Advance 2025 Paper 1

JEE Advance · 2025

94 questions · One at a time

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SHORT ANSWER4 marks

Single slit diffraction. bd/D=mλbd/D = m\lambda  . D=1D = 1   m (least count 1 cm), d=5d = 5   mm (least count 1 mm). Absolute error in bb   in μm\mu m   for m=3,λ=600m=3, \lambda=600   nm is:

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