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JEE Advance 2025 Paper 1

JEE Advance · 2025

94 questions · One at a time

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SHORT ANSWER4 marks

Let α,β\alpha, \beta   be real numbers such that limx01x3(α20x11t2dt+βxcosx)=2\lim_{x \to 0} \frac{1}{x^{3}} \left( \frac{\alpha}{2} \int_{0}^{x} \frac{1}{1-t^{2}} dt + \beta x \cos x \right) = 2  . Find α+β\alpha + \beta  .

Answer

2.4
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