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JEE Main PAPER - 1

JEE Main · 2018

180 questions · One at a time

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59
MCQ4 marks

Let A be the sum of the first 20 terms and B be the sum of the first 40 terms of the series 12+222+32+242+52+262+1^2 + 2 \cdot 2^2 + 3^2 + 2 \cdot 4^2 + 5^2 + 2 \cdot 6^2 + \dots  . If B2A=100λB - 2A = 100\lambda  , then λ\lambda   is equal to:

  • A.464
  • B.496
  • C.232
  • D.248Correct
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