JEE Main PAPER - 1

The ratio of mass percent of C and H of an organic compound $(C_xH_yO_z)$   is 6:1. If one molecule of the above compound $(C_xH_yO_z)$   contains half as much oxygen as required to burn one molecule of compound $C_xH_y$   completely to $CO_2$   and $H_2O$  . The empirical formula of compound $C_xH_yO_z$   is: