26MCQ1 markજો P એ △ABC\triangle ABC△ABC ના અંદરના ભાગમાં આવેલું કોઈ બિંદુ હોય તો અને તો જ Area(APB)+Area(BPC)=Area(APB) + Area(BPC) =Area(APB)+Area(BPC)=A.Area(ABC)−Area(BPC)Area(ABC)-Area(BPC)Area(ABC)−Area(BPC)B.Area(BPC)−Area(ABC)Area(BPC)-Area(ABC)Area(BPC)−Area(ABC)C.Area(ABC)−Area(CPA)Area(ABC)-Area(CPA)Area(ABC)−Area(CPA)CorrectD.Area(ABC)+Area(BPC)Area(ABC)+Area(BPC)Area(ABC)+Area(BPC)Log in to generate solution